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x^2+10x+21=(x-7)(x-3)
We move all terms to the left:
x^2+10x+21-((x-7)(x-3))=0
We multiply parentheses ..
x^2-((+x^2-3x-7x+21))+10x+21=0
We calculate terms in parentheses: -((+x^2-3x-7x+21)), so:We add all the numbers together, and all the variables
(+x^2-3x-7x+21)
We get rid of parentheses
x^2-3x-7x+21
We add all the numbers together, and all the variables
x^2-10x+21
Back to the equation:
-(x^2-10x+21)
x^2+10x-(x^2-10x+21)+21=0
We get rid of parentheses
x^2-x^2+10x+10x-21+21=0
We add all the numbers together, and all the variables
20x=0
x=0/20
x=0
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